Ψw(cell) = -0.8 + 0.3 = -0.5 MPa (higher than -0.6 MPa) → water leaves the cell. B. Transpiration Rate Formula: Transpiration rate = (water loss in g) / (leaf area in m² × time in h)
Calculate water potential of a cell with Ψs = -0.8 MPa and Ψp = 0.3 MPa. Will water enter or leave if placed in a solution of Ψw = -0.6 MPa? fizjologia roślin zadania
a) Ψw(cell) = –0.9 + 0.4 = –0.5 MPa b) Ψs(solution) = –iCRT = –1 × 0.2 × 0.00831 × 293 = –0.487 MPa; Ψp = 0 (open container) → Ψw = –0.487 MPa c) Cell Ψw (–0.5) < solution Ψw (–0.487) → water moves into the cell. 7. Quick Reference Card (for revision) | Process | Key equation / concept | |---------|------------------------| | Water potential | Ψw = Ψs + Ψp | | Osmosis | Water moves from high Ψw to low Ψw | | Transpiration | Driven by vapor pressure deficit | | Photosynthesis | 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂ | | Respiration | C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP | | Phloem transport | Source (high sugar) → Sink (low sugar) | | Phytochrome | Pr (red-absorbing, 660 nm) ↔ Pfr (far-red, 730 nm) | If you need specific types of problems (e.g., only osmosis, only photosynthesis calculations, or photoperiodism charts), let me know – I can provide a focused worksheet with answers. Ψw(cell) = -0
Leaf loses 1.2 g water in 2 hours, area = 0.01 m². Rate = 1.2 / (0.01 × 2) = 60 g·m⁻²·h⁻¹. C. Photosynthesis – Limiting Factors Task: At low CO₂, increasing light intensity does not increase photosynthesis – explain. Answer: CO₂ is limiting; RuBisCO cannot fix more CO₂ without substrate. Will water enter or leave if placed in
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