X Trench Run Math _best_ Today

[ P_\texthit = 1 - \exp\left( -\fracR^22\sigma^2 \right) ]

(h) (depth to target):

[ P_\texthit \approx 1 - e^-0.913 \approx 1 - 0.401 \approx 0.599 \ (\text59.9%) ] x trench run math

[ t = \fracL\textspeed = \frac60,000 \text m180 \text m/s \approx 333 \text seconds \ (\text5 min 33 sec) ] [ P_\texthit = 1 - \exp\left( -\fracR^22\sigma^2 \right)

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That’s extreme but possible with sci-fi tech — the key is precise timing. If the port is fixed in space but the X-wing moves laterally at speed (v_x), the torpedo must lead the target. the torpedo must lead the target.